# Livermorium(Lv) electron configuration and orbital diagram

Livermorium is the 116th element in the periodic table and its symbol is ‘Lv’. Livermorium is a classified post-transition metal element. The total number of electrons in livermorium is one hundred sixteen. These electrons are arranged according to specific rules of different orbits. The arrangement of electrons in different orbits and orbitals of an atom in a certain order is called **electron configuration**. The electron configuration of a livermorium(Lv) atom can be done in two ways.

- Electron configuration through orbit (Bohr principle)
- Electron configuration through orbital (Aufbau principle)

Electron configuration through orbitals follows different principles. For example Aufbau principle, Hund’s principle, and Pauli’s exclusion principle. The electron configuration and orbital diagram of livermorium is the main topic in this article. Hopefully, after reading this article you will know in detail about this.

## Livermorium atom electron configuration through orbit

Scientist Niels Bohr was the first to give an idea of the atom’s orbit. He provided a model of the atom in 1913. The complete idea of the orbit is given there. The electrons of the atom revolve around the nucleus in a certain circular path. These circular paths are called orbit(shell). These orbits are expressed by n. [n = 1,2,3,4 . . . The serial number of the orbit]

K is the name of the first orbit, L is the second, M is the third, and N is the name of the fourth orbit. The electron holding capacity of each orbit is 2n^{2}.

For example,

- n = 1 for K orbit.

The electron holding capacity of K orbit is 2n^{2}= 2 × 1^{2}= 2 electrons. - For L orbit, n = 2.

The electron holding capacity of the L orbit is 2n^{2}= 2 × 2^{2}= 8 electrons. - n=3 for M orbit.

The maximum electron holding capacity in M orbit is 2n^{2}= 2 × 3^{2 }= 18 electrons. - n=4 for N orbit.

The maximum electron holding capacity in N orbit is 2n^{2}= 2 × 4^{2}= 32 electrons.

Therefore, the maximum electron holding capacity in the first shell is two, the second shell is eight and the 3rd shell can have a maximum of eighteen electrons. The atomic number is the number of electrons in that element. The atomic number of livermorium is 116. That is, the number of electrons in livermorium is one hundred sixteen. Therefore, a livermorium atom will have two electrons in the first shell, eight in the 2nd orbit, eighteen electrons in the 3rd shell, and thirty-two in the 4th shell.

The fifth shell of livermorium will have thirty-two electrons, eighteen electrons in the sixth shell and the remaining six electrons will be in the seventh shell. Therefore, the order of the number of electrons in each shell of the livermorium(Lv) atom is 2, 8, 18, 32, 32, 18, 6. (predicted)

Electrons can be arranged correctly through orbits from elements 1 to 18. The electron configuration of an element with an atomic number greater than 18 cannot be properly determined according to the Bohr atomic model. The **electron configuration of all the elements** can be done through the orbital diagram.

## Electron configuration of livermorium through orbital

Atomic energy levels are subdivided into sub-energy levels. These sub-energy levels are called orbital. The sub energy levels are expressed by ‘l’. The value of ‘l’ is from 0 to (n – 1). The sub-energy levels are known as s, p, d, f. Determining the value of ‘l’ for different energy levels is-

- If n = 1,

(n – 1) = (1–1) = 0

Therefore, the orbital number of ‘l’ is 1; And the orbital is 1s. - If n = 2,

(n – 1) = (2–1) = 1.

Therefore, the orbital number of ‘l’ is 2; And the orbital is 2s, 2p. - If n = 3,

(n – 1) = (3–1) = 2.

Therefore, the orbital number of ‘l’ is 3; And the orbital is 3s, 3p, 3d. - If n = 4,

(n – 1) = (4–1) = 3

Therefore, the orbital number of ‘l’ is 4; And the orbital is 4s, 4p, 4d, 4f. - If n = 5,

(n – 1) = (n – 5) = 4.

Therefore, l = 0,1,2,3,4. The number of orbitals will be 5 but 4s, 4p, 4d, 4f in these four orbitals it is possible to arrange the electrons of all the elements of the periodic table. The electron holding capacity of these orbitals is s = 2, p = 6, d = 10 and f = 14. The German physicist Aufbau first proposed the idea of electron configuration through sub-orbits.

The Aufbau method is to do electron configuration through the sub-energy level. The Aufbau principle is that the electrons present in the atom will first complete the lowest energy orbital and then gradually continue to complete the higher energy orbital. These orbitals are named s, p, d, f. The Aufbau electron configuration method is 1s 2s 2p 3s 3p 4s 3d 4p 5s 4d 5p 6s 4f 5d 6p 7s 5f 6d.

The first two electrons of livermorium enter the 1s orbital. The s-orbital can have a maximum of two electrons. Therefore, the next two electrons enter the 2s orbital. The p-orbital can have a maximum of six electrons. So, the next six electrons enter the 2p orbital. The second orbit is now full. So, the remaining electrons will enter the third orbit.

Then two electrons will enter the 3s orbital and the next six electrons will be in the 3p orbital of the third orbit. The 3p orbital is now full. So, the next two electrons will enter the 4s orbital and ten electrons will enter the 3d orbital. The 3d orbital is now full. So, the next six electrons enter the 4p orbital. Then next ten electrons will enter the 4d orbital.

The 4d orbital is now full. So, the next eight electrons enter the 5p and 6s orbital. Then next fourteen electrons will enter the 4f orbital. The 4f orbital is now full of electrons. So, the next ten electrons will enter the 5d orbital and the next six electrons will enter the 6p orbital. The 6p orbital is now full. So, the next two electrons will enter the 7s orbital.

**Then next fourteen electrons will enter the 5f orbital and the next ten electrons will enter the 6d orbital. The 4d orbital is now full of electrons. So, the remaining four electrons enter the 7p orbital. Therefore, the livermorium(Lv) electron configuration will be 1s ^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 3d^{10} 4s^{2} 4p^{6} 4d^{10} 4f^{14} 5s^{2} 5p^{6} 5d^{10} 5f^{14} 6s^{2} 6p^{6} 6d^{10} 7s^{2} 7p^{4}.** (predicted)

## How to write the orbital diagram for livermorium?

To create an orbital diagram of an atom, you first need to know Hund’s principle and Pauli’s exclusion principle. Hund’s principle is that electrons in different orbitals with the same energy would be positioned in such a way that they could be in the unpaired state of maximum number and the spin of the unpaired electrons will be one-way.

And Pauli’s exclusion principle is that the value of four quantum numbers of two electrons in an atom cannot be the same. To write the orbital diagram of livermorium(Lv), you have to do the electron configuration of livermorium. Which has been discussed in detail above. 1s is the closest and lowest energy orbital to the nucleus. Therefore, the electron will first enter the 1s orbital.

According to Hund’s principle, the first electron will enter in the clockwise direction and the next electron will enter the 1s orbital in the anti-clockwise direction. The 1s orbital is now filled with two electrons. Then next two electrons will enter the 2s orbital just like the 1s orbital. The next three electrons will enter the 2p orbital in the clockwise direction and the next three electrons will enter the 2p orbital in the anti-clockwise direction.

Then next two electrons will enter the 3s orbital just like the 1s orbital and the next six electrons will enter the 3p orbital just like the 2p orbital. The 3p orbital is now full. So, the next two electrons will enter the 4s orbital just like the 1s orbital. Then next five electrons will enter the 3d orbital in the clockwise direction and the next five electrons will enter the 3d orbital in the anti-clockwise direction.

The 3d orbital is now full. So, the next six electrons will enter the 4p orbital just like the 2p orbital. Then next two electrons will enter the 5s orbital just like the 1s orbital and the next ten electrons will enter the 4d orbital just like the 3d orbital. The 4d orbital is now full of electrons. Then next eight electrons will enter the 5p and 6s orbital just like the 2p and 1s orbital.

The 6s orbital is now full of electrons. So, the next seven electrons will enter the 4f orbital in the clockwise direction and the next seven electrons will enter the 4f orbital in the anti-clockwise direction. The 4f orbital is now full. So, the next ten electrons will enter the 5d orbital just like the 3d orbital. Then next eight electrons will enter the 6p and 7s orbital just like the 2p and 1s orbital.

**The 7s orbital is now full of electrons. So, the next fourteen electrons will enter the 5f orbital just like the 4f orbital. Then next ten electrons will enter the 6d orbital just like the 3d orbital. Then next three electrons will enter the 7p orbital in the clockwise direction and the remaining one electron will enter the 7p orbital in the anti-clockwise direction. This is clearly shown in the figure of the orbital diagram of livermorium.**

## FAQ

What is the symbol for livermorium?**Ans:** The symbol for livermorium is ‘Lv’.

How many electrons does livermorium have?**Ans:** 116 electrons.

How do you write the electron configuration for livermorium?**Ans:** Livermorium electron configuration is 1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 3d^{10} 4s^{2} 4p^{6} 4d^{10} 4f^{14} 5s^{2} 5p^{6} 5d^{10} 5f^{14} 6s^{2} 6p^{6} 6d^{10} 7s^{2} 7p^{4}. (predicted)

**Reference**