Hydroxide ion Concentration Calculator from pH and pOH
The Hydroxide Ion Concentration Calculator is a versatile tool designed to facilitate the calculation of the hydroxide ion concentration ([OH–]) in a solution based on the given pH or pOH values.
This calculator is instrumental in understanding the basic principles of acid-base chemistry and provides insights into the alkalinity or basicity of a solution.
Welcome to the Hydroxide Ion Concentration Calculator
How to Use the Calculator?
Input Selection: Users have the flexibility to input either the pH or pOH value, choosing the appropriate selection from the dropdown menu.
Data Entry: Enter the pOH or pH value into the designated field.
Calculation: Upon clicking the “Calculate” button, the calculator swiftly processes the input and computes the corresponding [OH–] concentration and displays it along with the associated pH or pOH value.
Measuring Hydroxide Ion Concentration from pOH and pH
Relationship between pH, pOH, and Hydroxide Ion Concentration: The hydroxide ion concentration ([OH–]) in a solution can be calculated using the given pH or pOH values. Understanding the relationship between these parameters is fundamental:
pH and pOH Relationship: In an aqueous solution at 25°C, the sum of pH and pOH is always 14. This relationship remains constant due to the auto-ionization of water.
pH + pOH = 14
Calculating Hydroxide Ion Concentration [OH–] from pOH
Given the pOH value, the hydroxide ion concentration can be determined using the formula:
From pOH Equation: If the pOH of a solution is known, the [OH–] concentration can be calculated.
pOH = -log[OH–]
Example: For a solution with a pOH of 4:
- Using the pOH equation:
- pOH = 4
- -log[OH–] = 4
- [OH–] = 1.00 × 10-4 M
Calculating Hydroxide Ion Concentration [OH⁻] from pH
Similarly, [OH⁻] can be calculated when the pH is given using the relationship between pH and pOH:
From pH Equation: If the pH of a solution is provided, the [OH⁻] concentration can be deduced.
- pH + pOH = 14
- pOH = 14 – pH
Example: For a solution with a pH of 11.6:
- Using the pH + pOH equation:
- pH + pOH = 14
- 11.6 + pOH = 14
- pOH = 14 – 11.6
- pOH = 2.4
Further Calculation:
From the pOH equation:
- pOH = 2.4
- -log[OH⁻] = 2.4
- [OH⁻] = 2.51 × 10-12 M