{"id":5776,"date":"2022-11-18T00:31:26","date_gmt":"2022-11-17T18:31:26","guid":{"rendered":"https:\/\/valenceelectrons.com\/?p=5776"},"modified":"2023-09-08T23:50:48","modified_gmt":"2023-09-08T17:50:48","slug":"brf2-valence-electrons","status":"publish","type":"post","link":"https:\/\/valenceelectrons.com\/brf2-valence-electrons\/","title":{"rendered":"How to Find the Valence Electrons for BrF2 and BrF2+?"},"content":{"rendered":"\n
The total number of electrons in the last orbit of an element is called the valence electrons of that element. Two or more elements combine to form compounds.<\/p>\n\n\n\n
The valence electrons of a compound are the sum of the total valence electrons<\/a> of each element in that compound. Bromine difluoride consists of two atoms. One is a bromine atom and the other is a fluorine atom.<\/p>\n\n\n\n The valence electrons of\u00a0bromine difluoride are the sum of the total valence\u00a0electrons of bromine<\/a>\u00a0and fluorine in the compound BrF2<\/sub>. The bromine difluoride compound has a total of twenty-one electrons in the last\u00a0orbits of bromine<\/a>\u00a0and fluorine.<\/p>\n\n\n Hence, the total number of valence electrons in bromine<\/a> difluoride is twenty-one. To determine the valence electrons of a compound, the number of valence electrons in each element of the compound must be known.<\/p>\n\n\n\n This article discusses in detail how to determine the valence electrons of BrF2<\/sub>, BrF2<\/sub>–<\/sup>, and BrF2<\/sub>+<\/sup> very easily. Hopefully, after reading this article you will know more about this topic.<\/p>\n\n\n\n The symbol form of bromine difluoride is BrF2<\/sub>. To determine the valence electrons of BrF2<\/sub>, it is first necessary to know the valence electrons of the fluorine<\/a> and bromine atoms.<\/p>\n\n\n\n To determine the valence electrons of bromine difluoride we have to follow two steps. It is shown below:<\/p>\n\n\n\n The atomic number of bromine is 35. So its total number of electrons is thirty-five. The electron configuration<\/a> of bromine shows that it has seven electrons in its last orbit.<\/p>\n\n\n We already know that the electrons in the last orbit of an element are the valence electrons of that element. Therefore, the valence electrons of bromine are seven.<\/p>\n\n\n\n On the other hand, the atomic number of fluorine<\/a> is 9. So its total number of electrons is nine.<\/p>\n\n\n The\u00a0electron configuration of fluorine<\/a>\u00a0shows that it has seven electrons in its last orbit. Therefore, the valence electrons of fluorine are seven.<\/p>\n\n\n\n Try the Valence Electrons Calculator and get instant results for any element<\/a>.<\/p>\n<\/blockquote>\n<\/div><\/div>\n\n\n\n Bromine difluoride is a compound. It is composed of one bromine atom and two fluorine atoms.<\/p>\n\n\n\n Therefore, adding the valence electrons of one bromine atom and the valence electrons of two fluorine atoms<\/a> can easily determine the valence electrons of bromine difluoride.<\/p>\n\n\n\n Mathematical Analysis:<\/strong><\/p>\n\n\n\n BrF2<\/sub> From the above mathematical analysis, we can see that the total number of electrons in the outermost orbit of BrF2<\/sub> is twenty-one. Therefore, the valence electrons of BrF2<\/sub> are twenty-one.<\/p>\n\n\n\n The bromine difluoride compound has an unpaired electron. It is shown in the figure above. For this, bromine difluoride can accept or donate an electron.<\/p>\n\n\n\n BrF2<\/sub>+<\/sup> will have twenty valence electrons while bromine difluoride donates one electron.<\/p>\n\n\n\n Mathematical Analysis:<\/strong><\/p>\n\n\n\n BrF2<\/sub>+<\/sup> On the other hand, if bromine difluoride accepts one electron, the valence electrons of BrF2<\/sub>–<\/sup> will be twenty-two.<\/p>\n\n\n\n Mathematical Analysis:<\/strong><\/p>\n\n\n\n BrF2<\/sub>–<\/sup>How to easily determine the number of valence electrons of BrF2<\/sub>?<\/h2>\n\n\n\n
Step 1: Determine the valence electrons of bromine and fluorine atoms<\/h3>\n\n\n\n
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Step 2: Determine the total number of valence electrons in the bromine difluoride compound<\/h3>\n\n\n\n
= 7 + (7\u00d72)
= 21<\/p>\n\n\n\nBromine (Br)<\/strong><\/td> Fluorine (F)<\/strong><\/td> Bromine difluoride (BrF2<\/sub>)<\/strong><\/td><\/tr> 7<\/td> 7<\/td> 21<\/td><\/tr><\/tbody><\/table> How to determine the valence electrons of BrF2<\/sub>+<\/sup> and BrF2<\/sub>–<\/sup>?<\/h2>\n\n\n\n
= 7 + (7\u00d72) – 1
= 20<\/p>\n\n\n\n
= 7 + (7\u00d72) + 1
= 22<\/p>\n\n\n\nBrF2<\/sub><\/strong><\/td> BrF2<\/sub>+<\/sup><\/strong><\/td> BrF2<\/sub>–<\/sup><\/strong><\/td><\/tr> 21<\/td> 20<\/td> 22<\/td><\/tr><\/tbody><\/table> Why do you need to know the valence electrons of an element?<\/h2>\n\n\n\n